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发表于 2012-8-26 23:10:57
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回复 1# zqb138 的帖子
In the Maxwellian equilibrium e^{- (\xi - u )^2/2RT), where u and \xi are the flow velocity and the molecular velocity, respectively, and the is the temperature. The argument in the exponential is dimensionless. So when you use "c=dx/dt" as the unit of velocity, the thermal energy "RT" has to be expressed in terms of "c^2". In the equilibrium of LBE, all terms are dimensionless -- for they are the terms resulted from the Taylor expansion of the Maxwellian -- thus "c" naturally appears in the LBE equilibrium. |
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