请问k-e方程中风口(inlet)k,e是怎么取初值的?

ggssjj

问题1、
我发现k-e方程中风口(inlet)处k,e初值的选取对计算的影响太大了，请问各位平常都是怎么选取的？请介绍介绍经验！！有没有现成的公式？
问题2、
请问温度的松弛系数怎么选取的？phoenics中列举的例子有的选1000，有的选100，差距有这么大吗？
我今天把温度的松弛系数调到10，结果发现严重影响了室内温度场的分布。
请各位指教，多多感谢！！！！！

ronghua

where I is the turbulent intensity (typically in the range 0.01 < I < 0.05) and LM = 0.1H, where H is a characteristic inlet dimension, say the hydraulic radius of the inlet pipe.CMUCD=0.09
Ans2.
For a converged result,the temperature-distribution should be the same, so you should check your results again.

ronghua

Ans.1
The inlet values of KE and EP are often unknown, and the advice is to take guidance from experimental data for similar flows. The simplest practice is to assume uniform values of KE and EP computed from:
KE=(I*U)**2 , EP=(CMUCD)**0.75*KE**1.5/LM
where I is the turbulent intensity (typically in the range 0.01 < I < 0.05) and LM = 0.1H, where H is a characteristic inlet dimension, say the hydraulic radius of the inlet pipe.CMUCD=0.09
Ans. 2
For the converged results,the temperature-distribution should be the same, so you should check your results again.