一道maple解方程组的题

pkucoe

苦恼很久，不知如何求解，望大神指点
{C1+C2-1/(alpha^2*A1) = 0, C5/C6 = exp(2*alpha*sqrt(A3*M3))*`，`*exp(alpha*sqrt(A1)*sqrt(M1)*r)*C2+exp(-alpha*sqrt(A1)*sqrt(M1)*r)*C1-1/(alpha^2*A1) and exp(2*alpha*sqrt(A3*M3))*`，`*exp(alpha*sqrt(A1)*sqrt(M1)*r)*C2+exp(-alpha*sqrt(A1)*sqrt(M1)*r)*C1-1/(alpha^2*A1) = exp(alpha*sqrt(A2)*sqrt(M2)*r)*C4+exp(-alpha*sqrt(A2)*sqrt(M2)*r)*C3-`，`*exp(alpha*sqrt(A2)*sqrt(M2)*theta)*C4/(alpha^2*A2)+exp(-alpha*sqrt(A2)*sqrt(M2)*theta)*C3-1/(alpha^2*A2) and exp(alpha*sqrt(A2)*sqrt(M2)*r)*C4+exp(-alpha*sqrt(A2)*sqrt(M2)*r)*C3-`，`*exp(alpha*sqrt(A2)*sqrt(M2)*theta)*C4/(alpha^2*A2)+exp(-alpha*sqrt(A2)*sqrt(M2)*theta)*C3-1/(alpha^2*A2) = exp(alpha*sqrt(A3)*sqrt(M3)*theta)*C6+exp(-alpha*sqrt(A3)*sqrt(M3)*theta)*C5-`，`*(alpha*sqrt(A2)*sqrt(M2)*exp(alpha*sqrt(A2)*sqrt(M2)*theta)*C4-alpha*sqrt(A2)*sqrt(M2)*exp(-alpha*sqrt(A2)*sqrt(M2)*theta)*C3)/(alpha^2*A3*M2) and exp(alpha*sqrt(A3)*sqrt(M3)*theta)*C6+exp(-alpha*sqrt(A3)*sqrt(M3)*theta)*C5-`，`*(alpha*sqrt(A2)*sqrt(M2)*exp(alpha*sqrt(A2)*sqrt(M2)*theta)*C4-alpha*sqrt(A2)*sqrt(M2)*exp(-alpha*sqrt(A2)*sqrt(M2)*theta)*C3)/(alpha^2*A3*M2) = (alpha*sqrt(A3)*sqrt(M3)*exp(alpha*sqrt(A3)*sqrt(M3)*theta)*C6-alpha*sqrt(A3)*sqrt(M3)*exp(-alpha*sqrt(A3)*sqrt(M3)*theta)*C5)*`，`*(alpha*sqrt(A2)*sqrt(M2)*exp(alpha*sqrt(A2)*sqrt(M2)*theta)*C4-alpha*sqrt(A2)*sqrt(M2)*exp(-alpha*sqrt(A2)*sqrt(M2)*theta)*C3)/(M3*M2) and (alpha*sqrt(A3)*sqrt(M3)*exp(alpha*sqrt(A3)*sqrt(M3)*theta)*C6-alpha*sqrt(A3)*sqrt(M3)*exp(-alpha*sqrt(A3)*sqrt(M3)*theta)*C5)*`，`*(alpha*sqrt(A2)*sqrt(M2)*exp(alpha*sqrt(A2)*sqrt(M2)*theta)*C4-alpha*sqrt(A2)*sqrt(M2)*exp(-alpha*sqrt(A2)*sqrt(M2)*theta)*C3)/(M3*M2) = (alpha*sqrt(A3)*sqrt(M3)*exp(alpha*sqrt(A3)*sqrt(M3)*theta)*C6-alpha*sqrt(A3)*sqrt(M3)*exp(-alpha*sqrt(A3)*sqrt(M3)*theta)*C5)/M3}, 求解的未知数为{C1, C2, C3, C4, C5, C6}

uesoft

这个题好像也可以用Matlab符号计算工具箱求解。